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Question

Calculate the value of Avagadro's number if the density of NaCl is 2.165 g cm3 and distance between Na+ and Cl ions in NaCl crystal is 281 pm.

A
1.52×1023
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B
3.04×1023
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C
6.09×1023
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D
12.18×1023
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Solution

The correct option is D 6.09×1023

Density of NaCl =2.165 g/cc

Number of atoms in NaCl =4

FCC structure rNa++RCl=a2


281=0.3535 aa=794.9 pm =794.9×1010 cm
Molecular weight of NaCl =23+35.5=58.5 g/mol


d=z×ma3×NA


2.165=4×58.5(794.9×1010)3×NA


NA=4×58.5(794.9×1010)3×2.165


NA=6.09×1023

Hence, the value of the avogadro's number is 6.09×1023.

Hence, the correct option is C

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