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Question

# Calculate the value of Avagadro's number if the density of NaCl is 2.165 g cm−3 and distance between Na+ and Cl− ions in NaCl crystal is 281 pm.

A
1.52×1023
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B
3.04×1023
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C
6.09×1023
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D
12.18×1023
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Solution

## The correct option is D 6.09×1023Density of NaCl =2.165 g/ccNumber of atoms in NaCl =4 FCC structure rNa++RCl−=a2281=0.3535 a⇒a=794.9 pm =794.9×10−10 cmMolecular weight of NaCl =23+35.5=58.5 g/mold=z×ma3×NA2.165=4×58.5(794.9×10−10)3×NANA=4×58.5(794.9×10−10)3×2.165NA=6.09×1023Hence, the value of the avogadro's number is 6.09×1023.Hence, the correct option is C

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