Calculate the value of d for which 4d-3-9-8-10-2-d-6

The correct option is B 23/8 4(d + 3) #160; 98 = 10 (2 d)6 Cross multiplying, we get 6 × [4d + 12 9] = 8 × [10 2 + d] i.e. 3 × [4 ...

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Standard XII

Mathematics

Algebra of Complex Numbers

Calculate the...

Question

Calculate the value of $d$ for which

$\frac{4 (d + 3) - 9}{8} = \frac{10 - (2 - d)}{6}$

\frac{23}{16}

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\frac{23}{8}

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\frac{25}{8}

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\frac{25}{4}

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Solution

The correct option is B $\frac{23}{8}$
$\frac{4 (d + 3) - 9}{8} = \frac{10 - (2 - d)}{6}$
Cross multiplying, we get
$6 \times [4 d + 12 - 9] = 8 \times [10 - 2 + d]$
i.e. $3 \times [4 d + 3] = 4 \times [d + 8]$
$∴ 12 d + 9 = 4 d + 32$
$∴ 8 d = 32 - 9 = 23$
$∴ d = \frac{23}{8}$

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Similar questions

Q. The value of

d

which satisfies the expression

\frac{4 (d + 3) - 9}{8} = \frac{10 - (2 - d)}{6}

is:

In this case how many time intervals can Sid calculate?

$\begin{matrix} B u s & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 & 13 & 14 & 15 T i m e (h r : m i n) & 8 : 15 & 8 : 18 & 8 : 23 & 8 : 29 & 8 : 32 & 8 : 40 & 8 : 45 & 8 : 52 & 8 : 54 & 9 : 00 & 9 : 07 & 9 : 13 & 9 : 20 & 9 : 25 & 9 : 32 \end{matrix}$

Q. Express

{[(2^{1 / 2} . 4^{3 / 4} . 8^{5 / 6} . 16^{7 / 8} . 32^{9 / 10})^{4}]}^{8 / 25}

as an integer.

The mean of the following data is 8.
$\begin{matrix} x & 3 & 5 & 7 & 9 & 11 & 13 y & 6 & 8 & 15 & p & 8 & 4 \end{matrix}$
then, the value of p is
(a) 23
(b) 24
(c) 25
(d) 21

Q. Calculate the median for the following data.

Marks	$20$	$9$	$25$	$50$	$40$	$80$
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Calculate the value of d for which4(d+3)−98=10−(2−d)6

The correct option is B 2384(d+3)−98=10−(2−d)6Cross multiplying, we get6×[4d+12−9]=8×[10−2+d]i.e. 3×[4d+3]=4×[d+8]∴12d+9=4d+32∴8d=32−9=23∴d=238

Calculate the value of $d$ for which

$\frac{4 (d + 3) - 9}{8} = \frac{10 - (2 - d)}{6}$

The correct option is B $\frac{23}{8}$
$\frac{4 (d + 3) - 9}{8} = \frac{10 - (2 - d)}{6}$
Cross multiplying, we get
$6 \times [4 d + 12 - 9] = 8 \times [10 - 2 + d]$
i.e. $3 \times [4 d + 3] = 4 \times [d + 8]$
$∴ 12 d + 9 = 4 d + 32$
$∴ 8 d = 32 - 9 = 23$
$∴ d = \frac{23}{8}$