Calculate the value of j+n, if the length of the major axis of an ellipse with the equation 5x2+24y2=40 is j and the length of the minor axis of the ellipse is n.
A
2.58
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B
5.66
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C
6.95
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D
8.24
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E
9.78
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Solution
The correct option is D8.24 Given, 5x2+24y2=40 ⇒x28+y25/3=1 The length of major axis is 2×√8=5.657=j The length of minor axis is 2×√53=2.582=n ∴j+n=5.657+2.582=8.24