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Question

Calculate the value of Qc value, for the given reaction below. Also, given the concentration of all the species involved at a certain time:
CO (g)+H2O (g)CO2 (g)+H2 (g)[CO2]=2 M[H2]=2 M[CO]=1 M[H2O]=1 M

If Kc=1 , in which direction the reaction will shift to attain equilibrium?

A
QC=2 and forward
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B
QC=2 and backward
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C
QC=4 and forward
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D
QC=4 and backward
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Solution

The correct option is D QC=4 and backward
We know for a reaction:
aA (g)+bB (g)cC (g)+dD (g)
In terms of Concentration :
Qc=[C]c[D]d[A]a[B]b

So, In this case,
Qc=[CO2].[H2][CO].[H2O]=2×21×1=4
Comparing Qc and Kc
Since, Qc>Kc the reaction shifts backwards (to the reactants side) for attaining equilibrium.

Theory:
Reaction quotient :
The reaction quotient (Q) measures the relative amounts of products and reactants present during a reaction at a particular point in time.
Reaction :
aA (g)+bB (g)cC (g)+dD (g)
In terms of Partial Pressure :
Qp=[P]cc[P]dd[P]aa[P]bb
In terms of Concentration :
Qc=[C]c[D]d[A]a[B]b

Applications of Reaction quotient :
Case 1 :-
Qc>Kc
For the given reaction :
RP

If Qc>Kc or if QcKc this means that system is not in equilibrium.
Qc will move close toward Kc until it becomes equal to Kc.
Value of Kc(equilibrium constant) remains constant.
It promotes backward reaction when Qc>Kc to attain equilibrium.

Case 2 :- Qc<Kc
For the given reaction :
RP

If Qc<Kc or if QcKc this means that system is not in equilibrium.
Qc will move close toward Kc until it becomes equal to Kc. It promotes forward reaction when Qc<Kc to attain equilibrium.

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