Question

Calculate the value of $\sqrt[3]{3-64}+\sqrt{9^2}$.

• A. $-4$
• B. $3$
• C. $5$
• D. $77$

Answer 1

The correct option is C $5$

On prime factorising, we get,

$-64=(-4)\times (-4)\times (-4)$ $=(-4{)}^3$.

Then,

$\sqrt[3]{3-64}+\sqrt{9^2}=\sqrt[3]{3(-4{)}^3}+9=-4+9=5$.

Hence, option $C$ is correct.