Question

Calculate the value of $\sqrt[3]{3\frac{-192}{81}}$

• A. $-\frac{5}{3}$
• B. $\frac{-4}{3}$
• C. $\frac{3}{2}$
• D. $\frac{13}{9}$

Answer 1

The correct option is B $\frac{-4}{3}$

$\sqrt[3]{3\frac{-192}{81}}$ $=\sqrt[3]{3\frac{(-2)\times (-2)\times (-2)\times 2\times 2\times 2\times 3}{3\times 3\times 3\times 3}}$
$=\frac{-2\times 2}{3}=\frac{-4}{3}$