Question

Calculate the value of the acceleration due to gravity at a place $3,200km$ above the surface of the earth.

Answer 1

The acceleration due to gravity varies with height as

$g=g\left(\frac{R^2}{{\left(R+h\right)}^2}\right)$

By substituting the values in the above given equation we get

$g=9.8\left(\frac{{\left(6.4\times {10}^6\right)}^2}{{\left(6.4\times {10}^6+3.2\times {10}^6\right)}^2}\right)$

On solving the above equation we get the value of acceleration due to gravity at height of $3200km$

$g=4.4m/s^2$