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Characteristics of Equilibrium Constant

Calculate the...

Question

Calculate the value of the equilibrium constant for the reaction below if there are present at equilibrium 5.0 mol of $N_{2}$ , 7.0 mol of $O_{2}$ , and 0.10 mol of $N O_{2}$ in a 1.5 L vessel at a certain temperature.
$N_{2} + 2 O_{2} \to 2 N O_{2} + h e a t$

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Solution

$N_{2} (g) + O_{2} (g) ⟶ 2 N O (g) + h e a t$
Initially $5$ $7$ $0$
at equilibrium $5 - 0.1$ $7 - 0.1$ $0.1$
So,
$K_{C} = \frac{{[N O]}^{2}}{[N_{2}] {[O_{2}]}^{2}}$
$\Rightarrow K_{C} = \frac{{[0.1]}^{2}}{(5 - 0.1) {(7 - 0.1)}^{2}}$
$\Rightarrow K_{C} = 4.28$ mol/L
Total volume is $1.5 L$ .

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