Calculate the value of the expression using suitable identities $4 \times 2 \times (3^{2} + 1^{2})$

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Solution

The correct option is B
80

The given expression is

$4 \times 2 \times (3^{2} + 1^{2})$

$= (3 + 1) \times (3 - 1) \times (3^{2} + 1^{2})$

$= (3^{2} - 1^{2}) (3^{2} + 1^{2}) [(a + b) (a - b) = a^{2} - b^{2}]$

$= (3^{2})^{2} - (1^{2})^{2}$

$= 3^{4} - 1$

$= 81 - 1$

$= 80$

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