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Question

Calculate the value of the expression using suitable identities 4×2×(32+12)


A

79

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B

80

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C

78

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D

81

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Solution

The correct option is B

80


The given expression is

4×2×(32+12)

=(3+1)×(31)×(32+12)

=(3212)(32+12) [(a+b)(ab)=a2b2]

=(32)2(12)2

=341

=811

=80


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