The correct option is A 2.34 mA, 11.7 V
As given in the circuit,
Voltage, V=12 V and Resistance, R=5 kΩ
In the initial connection, the current will flow through the Ge diode, so
I=12−0.35×103=11.75×103
=2.34×10−3 A=2.34 mA
Output voltage,
V0=IR=V−VGe=12−0.3=11.7 V
Hence, (A) is the correct answer.