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Question

Calculate the values of the determinants:
∣ ∣b+caabc+abcca+b∣ ∣.

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Solution

Δ=∣ ∣b+caabc+abcca+b∣ ∣R1=R1R2R3Δ=∣ ∣02c2bbc+abcca+b∣ ∣
Expanding along R1
Δ=0(2c){b(a+b)bc)}+(2b){bcc(c+a)}Δ=2bc(a+bc)2bc(bca)Δ=2bc(a+bcb+c+a)Δ=4abc

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