Question

Calculate the velocity of efflux of kerosene oil from an orifice of a tank in which pressure is $4atm$. The density of kerosene oil $=720kg{m}^{-3}$ and $1$ atmospheric pressure $=1.013\times {10}^{5}N{m}^{-2}$.

• A. $3.355m/s$
• B. $33.55m/s$
• C. $335.5m/s$
• D. $33.55cm/s$

Answer 1

The correct option is B $33.55m/s$

From Bernoulli's Theorem,
$P_1=\frac{1}{2}\rho v^2$
$\Rightarrow 4atm=\frac{1}{2}\times \rho V^2$
$\Rightarrow \frac{4\times 1.013\times {10}^5\times 2}{720}=V^2$
$\Rightarrow V=33.549m/s$
$\Rightarrow V\approx 33.55m/s$