Calculate the velocity of the bob of a simple pendulum at its mean position if it is able to rise to a vertical height of $10 c m$ . Given: $g = 980 c m s^{- 2}$ .

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Solution

Given that,

Height h =10 cm

Now,

Kinetic energy at mean position = potential energy at maximum height

$\frac{1}{2} m v^{2} = m g h$

$v^{2} = 2 g h$

$v = \sqrt{2 g h}$

$v = \sqrt{2 \times 9.8 \times 0.1}$

$v = 1.4 m / s$

Hence, the velocity of the bob is $1.4 m / s$

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Calculate the velocity of the bob of a simple pendulum at its mean position if it is able to rise to a vertical height of 10 cm. Given: g=980 cms−2.

Given that, Height h =10 cm Now, Kinetic energy at mean position = potential energy at maximum height 12mv2=mgh v2=2gh v=√2gh v=√2×9.8×0.1 v=1.4m/s Hence, the velocity of the bob is 1.4 m/s

Calculate the velocity of the bob of a simple pendulum at its mean position if it is able to rise to a vertical height of $10 c m$ . Given: $g = 980 c m s^{- 2}$ .

Given that,

Height h =10 cm

Now,

Kinetic energy at mean position = potential energy at maximum height

$\frac{1}{2} m v^{2} = m g h$

$v^{2} = 2 g h$

$v = \sqrt{2 g h}$

$v = \sqrt{2 \times 9.8 \times 0.1}$

$v = 1.4 m / s$

Hence, the velocity of the bob is $1.4 m / s$