Calculate the velocity ratio of a machine which overcomes a resistance of 800N through a distance of 0.12m, while an effort of 160N acts through a distance of 0.72m.

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Solution

1. Definition:
Velocity ratio:(V.R)
It is the ratio of distance traveled by the effort to the distance traveled by the load.
Velocity ratio = $\frac{e f f o r t a r m}{l o a d a r m}$
2. Solution:
Given that,
load = 800N
Effort = 160N
Load arm = 0.12m
effort arm = 0.72m
Velocity ratio = $\frac{e f f o r t a r m}{l o a d a r m}$ = $\frac{0.72}{0.12}$ = 6
3. Conclusion:
Hence, the velocity ratio is 6.

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