Calculate the vertical height of a mercury column (in m) which exerts a pressure of $81600 P a$ . (Density of mercury is $13.6 g$ ${c m}^{- 3}$ and $g = 10 m$ $s^{- 2}$ ).

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Solution

Pressure = 81600 $P_{a}$
& Pressure = $ϱ g h = 13600 k g / m^{3} \times 10 \times h = 81600$
$h = \frac{81600 P_{a}}{13600 k g / m^{3} \times 10 m / s^{2}}$
$h = 0.6 m$

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Calculate the vertical height of a mercury column (in m) which exerts a pressure of 81600Pa. (Density of mercury is 13.6g cm−3 and g=10m s−2).

Pressure = 81600 Pa& Pressure = ϱgh=13600kg/m3×10×h=81600 h=81600Pa13600kg/m3×10m/s2 h=0.6m

Calculate the vertical height of a mercury column (in m) which exerts a pressure of $81600 P a$ . (Density of mercury is $13.6 g$ ${c m}^{- 3}$ and $g = 10 m$ $s^{- 2}$ ).

Pressure = 81600 $P_{a}$
& Pressure = $ϱ g h = 13600 k g / m^{3} \times 10 \times h = 81600$
$h = \frac{81600 P_{a}}{13600 k g / m^{3} \times 10 m / s^{2}}$
$h = 0.6 m$