Calculate the voltage E- of the cell- in V at 25-C Mns - MnOH2s -Mn2-x M- OH-1-00- 10-4M- - Cu2-0-675 M - Cusgiven that Ksp-1-9- 10-13 for MnOH2s E- Mn2-Mn-1-18 V- E-Cu2-Cu-0-34 V write the value to the nearest integer

E^o_cell=E^o_Cu E^o_Mn=0.34 ( 1.8)=1.52V K_sp = 1.9 × 10^ 13 [OH^ ]=1 × 10^ 4 K_sp = [Mn^2+][OH^ ]^2 1.9 × 10^ 13 =c × (10^ 4)^2 [ ...

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Nernst Equation

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Question

Calculate the voltage E, of the cell, in V at $25^{\circ} C$
$M n (s) | M n (O H_{2}) (s) | M n^{2 +} (x M), O H^{-} (1.00 \times 10^{- 4} M) | ∣ ∣ C u^{2 +} (0.675 M) ∣ ∣ C u (s)$
given that $K_{s p} = 1.9 \times 10^{- 13}$ for $M n (O H)_{2} (s) E^{\circ} (M n^{2 +} / M n) = - 1.18 V, E^{\circ} (C u^{2 +} / C u) = + 0.34 V$ (write the value to the nearest integer)

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Solution

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K_{c}

C u^{2 +} (a q) + S n^{2 +} (a q) ⟶ S n^{4 +} (a q) + C u (s)

25^{\circ} C

E_{C u^{2 +} | C u}^{\circ} = 0.34 V; E_{S n^{4 +} | S n^{2 +}}^{\circ} = 0.15 V

M n^{2 +} + 2 e^{-} \to M n; E^{\circ} = - 1.18 V

2 (M n^{3 +} + e^{-} \to M n^{2 +}); E^{\circ} = + 1.51 V

E^{\circ}

3 M n^{2 +} \to M n + 2 M n^{3 +}

E_{C e l l}^{o}

Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)

E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

E_{C u^{2 +} / C u}^{\circ} = 0.337 V and E_{C u^{+} / C u^{2 +}}^{\circ} = - 0.153 V

E_{C u^{+} / C u}^{\circ}

C u S, K_{s p} = 8.5 \times 10^{- 36}, E_{C u | C u^{2 +}}^{⊖} = - 0.34 V

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