Calculate the volume in litres occupied by $7.40 g$ of ammonia at $S T P$ (molar mass of ${N H}_{3} = 17 g {m o l}^{- 1}$ )

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Solution

$P V = \frac{m}{M} R T V = \frac{m R T}{M P} = \frac{7.4 \times 0.0821 \times 273}{17 \times 0.9869} = \frac{165.86}{16.7773} V = 9.8 L$

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Q. Statement 1 : Ammonia gas,

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S T P

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Calculate the volume in litres occupied by 7.40g of ammonia at STP (molar mass of NH3=17gmol−1)

PV=mMRTV=mRTMP=7.4×0.0821×27317×0.9869=165.8616.7773V=9.8L

Calculate the volume in litres occupied by $7.40 g$ of ammonia at $S T P$ (molar mass of ${N H}_{3} = 17 g {m o l}^{- 1}$ )

$P V = \frac{m}{M} R T V = \frac{m R T}{M P} = \frac{7.4 \times 0.0821 \times 273}{17 \times 0.9869} = \frac{165.86}{16.7773} V = 9.8 L$