wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the volume occupied by 2.0 mole of N2 at 200 K and 8.21 atm pressure, if PCVCRTC=38 and PrVrTr=2.4.

Open in App
Solution

First we will calculate the volume occupied by two moles of nitrogen at STP. We know that one mole of every gas occupies a volume of 22.4 liters at STP.
Therefore volume occupied by 2 moles of nitrogen at STP will be 2×22.4=44.8 liters
STP stands for standard temperature and pressure. For STP condition, the temperature is 273.15 K(0oC) and pressure is 1 bar(105 Pascals or 0.987 atm)
We will now use the relation
P1V1T1=P2V2T2
Here,
P1=0.987 atm
V1=44.8 litres
T1=273.15 K
P2=8.21 atm
T2=200 K
V2=?
Substituting in above equation, we get
0.987×44.8273.15=8.21×V2200
V2=0.987×44.8×200273.15×8.21
V2=3.94 liters

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Ideal Gas Equation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon