Calculate the volume occupied by 2.0 mole of $N_{2}$ at 200 K and 8 atm pressure if $\frac{P_{c} V_{c}}{R T_{c}} = \frac{3}{8}$ and $\frac{P_{r} V_{r}}{T_{r}} = 2.4$

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Solution

Number of moles of $N_{2}$ , $n = 2$ moles
Pressure, $P = 8 a t m$
Temperature, $T = 200 K$
We know that, $P V = n R T$
$\Rightarrow V = \frac{2 mole \times 0.0821 lit atm m o l e^{- 1} K^{- 1} \times 200 K}{8 a t m}$
$\Rightarrow V = 4.105 l i t r e$
$∴$ The volume occupied by $N_{2}$ will be $4.105$ litre.

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Calculate the volume occupied by 2.0 mole of N2 at 200 K and 8 atm pressure if PcVcRTc=38 and PrVrTr=2.4

Number of moles of N2, n=2 molesPressure, P=8atmTemperature, T=200KWe know that, PV=nRT⇒V=2 mole×0.0821 lit atm mole−1K−1×200K8atm⇒V=4.105litre∴ The volume occupied by N2 will be 4.105 litre.

Calculate the volume occupied by 2.0 mole of $N_{2}$ at 200 K and 8 atm pressure if $\frac{P_{c} V_{c}}{R T_{c}} = \frac{3}{8}$ and $\frac{P_{r} V_{r}}{T_{r}} = 2.4$