Calculate the volume occupied by 2 g of hydrogen at 27-C and 4 atmosphere pressure- if at S-T-P- it occupies 22-4 litres-

Moles of hydrogen = 2/2 = 1 mol Temperature = 27 + 273 = 300K PV = nRT V = nRT / P V = (1 × 0.0821× 300) / 4 V = 6.1575 L ...

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Standard IX

Chemistry

The Ideal Gas Equation

Calculate the...

Question

Calculate the volume occupied by 2 g of hydrogen at $27^{\circ} C$ and 4 atmosphere pressure, if at S.T.P. it occupies 22.4 litres.

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Solution

Moles of hydrogen = 2/2 = 1 mol
Temperature = 27 + 273 = 300K

PV = nRT
V = nRT / P
V = (1 $\times$ 0.0821 $\times$ 300) / 4
V = 6.1575 L

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Molar volume is the volume occupied by 1 mol of any (ideal) gas at standard temperature and pressure (STP: 1 atmospheric pressure, 0 °C). Show that it is 22.4 litres.

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Calculate the volume occupied by 2 g of hydrogen at 27∘C and 4 atmosphere pressure, if at S.T.P. it occupies 22.4 litres.

Moles of hydrogen = 2/2 = 1 mol Temperature = 27 + 273 = 300K PV = nRT V = nRT / P V = (1 × 0.0821× 300) / 4 V = 6.1575 L

Calculate the volume occupied by 2 g of hydrogen at $27^{\circ} C$ and 4 atmosphere pressure, if at S.T.P. it occupies 22.4 litres.

Moles of hydrogen = 2/2 = 1 mol
Temperature = 27 + 273 = 300K

PV = nRT
V = nRT / P
V = (1 $\times$ 0.0821 $\times$ 300) / 4
V = 6.1575 L