Calculate the volume occupied by 2 g of hydrogen at 27- C and 4 atmosphere pressure- if at S-T-P- it occupies 22-4 litres-

If at S.T.P. it occupies 22.4L volume, it is an ideal gas.Ideal gas law, #160; PV= nRT Here, n = 2/2= 1 mole, T= 27+273= 300K, R= 0.0820L ...

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Standard XII

Chemistry

Gay Lussac's Law, Avagadro's Law

Calculate the...

Question

Calculate the volume occupied by $2 g$ of hydrogen at $27^{\circ} C$ and $4$ atmosphere pressure, if at S.T.P. it occupies $22.4$ litres.

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Solution

If at S.T.P. it occupies 22.4L volume, it is an ideal gas.
Ideal gas law, $P V = n R T$
Here, $n = 2 / 2 = 1 m o l e, T = 27 + 273 = 300 K, R = 0.0820 L a t m m o l^{- 1} K^{- 1}, P = 4 a t m$

$V = \frac{1 \times 0.0820 \times 300}{4} = 6.15 L$

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Molar volume is the volume occupied by 1 mol of any (ideal) gas at standard temperature and pressure (STP: 1 atmospheric pressure, 0 °C). Show that it is 22.4 litres.

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Calculate the volume occupied by 2g of hydrogen at 27∘C and 4 atmosphere pressure, if at S.T.P. it occupies 22.4 litres.

If at S.T.P. it occupies 22.4L volume, it is an ideal gas.Ideal gas law, PV=nRTHere, n=2/2=1 mole,T=27+273=300K,R=0.0820L atm mol−1K−1,P=4 atmV=1×0.0820×3004=6.15L

Calculate the volume occupied by $2 g$ of hydrogen at $27^{\circ} C$ and $4$ atmosphere pressure, if at S.T.P. it occupies $22.4$ litres.

If at S.T.P. it occupies 22.4L volume, it is an ideal gas.
Ideal gas law, $P V = n R T$
Here, $n = 2 / 2 = 1 m o l e, T = 27 + 273 = 300 K, R = 0.0820 L a t m m o l^{- 1} K^{- 1}, P = 4 a t m$

$V = \frac{1 \times 0.0820 \times 300}{4} = 6.15 L$