Calculate the volume occupied by 200 $g$ of $S O_{3}$ gas at $S T P$ .

44.8 L

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33.6 L

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56 L

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67.2 L

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Solution

The correct option is C $56 L$
Volume occupied by 80 $g$ of $S O_{3}$ at $S T P$ = 22.4 $L$

Thus the volume occupied by 200 $g$ of $S O_{3}$ = $\frac{22.4 \times 200}{80}$ = 56 $L$

Hence, the correct option is $C$

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