Calculate the volume occupied by 320 g of sulphur dioxide at STP.

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Solution

The weight of sulphur dioxide $({SO}_{2})$ is $320 g m .$
$M o l e c u l a r w e i g h t o f S O_{2} = (32) + (2 \times 16)$
$= 64$
First calculate the number of moles, in $320 g m o f S O_{2}$ .

$n u m b e r o f m o l e s = \frac{W e i g h t}{M o l e c u l a r w e i g h t}$

$n u m b e r o f m o l e s = \frac{320}{64}$
$= 5 m o l e s$
$1 m o l e c o n t a i n s 22.4 l i t e r s a t S T P .$
$5 m o l e c o n t a i n s = 22.4 \times 5$
$= 112 l i t e r s .$
Hence, we get that volume occupied by 320 g of sulphur dioxide is 112 litres.

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