Question

Calculate the volume occupied by $7g$ of nitrogen gas at ${27}^{\circ }C$ and $750mmHg$ pressure.

Answer 1

Moles of Nitrogen = Weight / Molar mass

= 7 g / (28 g/mol)

= 0.25 mol

Pressure = 750 mm Hg

= (750/760) atm ………[∵ 1 atm = 760 mm Hg]

= 75/76 atm

From ideal gas equation

$V=\frac{nRT}{P}$

$=$ $\frac{0.25mol\times 0.0821atm.L/\left(molK\right))}{\left(75/76atm\right)}\times 300K$

$=6.2396$ liters

The volume occupied by the gas is 6.2396 litres