Calculate the volume occupied by $8.8 g$ of ${C O}_{2}$ at $31. 1^{o} C$ and 1 bar pressure. ( $R = 0.083$ bar ${d m}^{3} K^{- 1} {m o l}^{- 1})$

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Solution

Molecular weight of $C O_{2} = 44 g$
Weight of $C O_{2} = 8.8 g$
$∴$ no. of moles of $C O_{2}, (n) = \frac{w t .}{mol. wt.} = \frac{8.8}{44} = 0.2$
Given that:-
Pressure, $(P) = 1 b a r$
Volume, $(V) = ?$
Temperature, $(T) = 31.1 ℃ = (273 + 31.1) K = 304.1 K$
$R = 0.083 b a r {d m}^{3} K^{- 1} {m o l}^{- 1}$
From ideal gas equation,
$P V = n R T$
$\Rightarrow 1 \times V = 0.2 \times 0.083 \times 304.1$
$\Rightarrow V = 0.0166 {d m}^{3}$

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