Calculate the volume occupied by 8 g of sulphur dioxide at S.T.P.

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Solution

1 mole of any gas at S.T.P = 22.4 L
Also, 1 mole of any gas = Molecular mass of gas.
1 mole of ${SO}_{2}$ at S.T.P = 22.4 L
Also, 1 mole of ${SO}_{2}$ = Molecular mass of ${SO}_{2}$
The molecular mass of ${SO}_{2}$ = ( Mass of $S + 2 \times$ mass of $O$ )
= ( $32 + 2 \times 16$ )
Molecular mass of ${SO}_{2}$ = 64g
$\Rightarrow$ 64g of ${SO}_{2}$ occupies = 22.4 L
$∴$ 8g of ${SO}_{2}$ occupies= $\frac{22.4}{64} \times 8$
8g of ${SO}_{2}$ occupies 2.8 L

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A flask contains 3.2 g of sulphur dioxide. Calculate the following :

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A flask conntains 3.2g of sulphur dioxide calculate the following

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