Question

Calculate the volume occupied by the following sample of gases at STP
1) 2.5g moles of ozone
2) 3 moles of nitrogen
3) 3.2g of methane molecules
4) 2.2g of nitrous oxide molecules
5) 1.2*10 power 24 molecules of SO2 molecules
6) 3.011*10 power 21 molecules of carbon monoxide molecules

Answer 1

$$\begin{gathered} 1moleofanygasoccupies22.4LatSTP. \\ 1)2.5gmoleofozone=2.5moleofozone \\ Volumeoccupiedby2.5moleofozone=2.5\times 22.4=56L \\ 2)3molesofnitrogen \\ Volumeoccupiedby3molesofnitrogen=3\times 22.4=67.2L \\ 3)3.2gofmethane \\ Mole=\frac{weightofthegivensubs\tan ceing}{molarmass}=\frac{3.2}{16}=0.2 \\ Volumeoccupiedby0.2moleofmethane=0.2\times 22.4=4.48L \\ 4)2.2gofnitrousoxide \\ Mole=\frac{weightofthegivensubstanceing}{molarmassof{N}_{2}O}=\frac{2.2}{44}=0.05 \\ Volumeoccupiedby0.05moleofnitrousoxide=0.2\times 22.4=4.48L \\ 5)1.2\times {10}^{24}moleculesofS{O}_{2}molecule \\ Mole=\frac{Givenmolecule}{Avogadronumber}=\frac{1.2\times {10}^{24}}{6.022\times {10}^{23}}=0.2\times 10=2 \\ Thevolumeoccupiedby2moleofS{O}_2=2\times 22.4=44.8L \\ 6)3.011\times {10}^{21}moleculesofCOmolecule \\ Mole=\frac{Givenmolecule}{Avogadronumber}=\frac{3.011\times {10}^{21}}{6.022\times {10}^{23}}=0.5\times {10}^{-2} \\ Thevolumeoccupiedby0.5\times {10}^{-2}moleofCO=0.5\times {10}^{-2}\times 22.4=0.112L \end{gathered}$$