Question

Calculate the volume ocupied by $5.25g$ of nitrogen of ${26}^{o}C$ and $74.2cm$ of pressure.

Answer 1

P= 74.2/76 atm
V=?
m=5.25 g
M = 28 g
T=273+26=299K
PV=nRT
$\frac{74.2}{76}\times V=\frac{m}{M}\times 0.0821\times 299$
$V=5.25\times 0.0821\times 299\times \frac{76}{74.2}$
$V=4.710L$