Question

Calculate the volume of 0.015 M HCl solution required to prepare 250 mL of a $5.25\times {10}^{-3}$ M HCl solution.

• A. 63.4 mL
• B. 87.5 mL
• C. 26.4 mL
• D. 28.0 mL

Answer 1

The correct option is B 87.5 mL

$M_1{V}_1=M_2{V}_2$
Where,
$M_1\Rightarrow$ The molarity of the initial solution = 0.015 M
$V_1\Rightarrow$ The volume of the initial solution
$M_2\Rightarrow$ The molarity of the resultant solution = $(5.25\times {10}^{-3})$ M
$V_2\Rightarrow$The volume of the resultant solution = 250 mL
$0.015M\times V_1=5.25\times {10}^{-3}M\times 250$ mL
$V_1=\frac{5.25\times {10}^{-3}\times 250}{0.015}$
= 87.5 mL