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Byju's Answer
Standard XII
Chemistry
Oxidising Reagent and Reducing Reagent
Calculate the...
Question
Calculate the volume of
0.1
M
K
M
n
O
4
required to reach with
100
m
l
of
0.1
M
H
2
C
2
O
4
.2
H
2
O
solution in ?
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Solution
2
K
M
n
O
4
+
5
H
2
C
2
O
4
.2
H
2
O
+
H
2
S
O
4
⇌
2
M
n
S
O
4
+
K
2
S
O
4
+
10
C
O
2
+
10
H
2
O
Two moles of
K
M
n
O
4
reacts with 5 moles of oxalic acid.
M
1
V
1
=
M
2
V
2
2
(
0.1
∗
V
1
)
=
5
(
0.1
∗
100
)
0.2
∗
V
1
=
50
=
>
x
=
250
m
l
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0
Similar questions
Q.
50 ml of
H
2
O
2
solution when titrated with 0.1 M
K
M
n
O
4
solution in acidic medium, volume required is 40 ml. Volume strength of
H
2
O
2
solution is
Q.
A solution of
0.1
M
K
M
n
O
4
is used for the reaction,
S
2
O
2
−
3
+
2
M
n
O
−
4
+
H
2
O
⟶
M
n
O
2
+
S
O
2
−
4
+
O
H
−
. What volume of solution in mL will be required to react with
0.158
g
of
N
a
2
S
2
O
3
? (in mL as nearest integer)
Q.
100
m
l
0.1
M
H
2
O
2
is mixed with
400
m
l
0.5
M
H
2
O
2
. The volume of
0.1
M
K
M
n
O
4
(acidic) required to react with
H
2
O
2
mixture is :
Q.
Potassium acid oxalate
K
2
C
2
O
4
.
3
H
2
C
2
O
4
.4
H
2
O
can be oxidized by
M
n
O
−
4
in acid medium. Calculate the volume in litresof
0.1
M
K
M
n
O
4
reacting in acid solution with
5.08
g
m
of the acid oxalate.
Q.
The volume in ml of
0.1
M
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N
a
O
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required to completely neutralize
100
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0.3
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solution of
H
3
P
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Standard XII Chemistry
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