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Molecular Mass

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Question

Calculate the volume of $0.1 N H_{2} S O_{4}$ required to neutralized $200 m l$ of $0.2 N N a O H$ solution.

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Solution

$N_{1} V_{1} = N_{2} V_{2}$
$V_{1} = \frac{0.2 \times 200}{0.1} = 400 m l .$
Volume of $H_{2} S O_{4}$ required $= 400 m l .$

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