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Question

Calculate the volume of 1 M aqueous sodium hydroxide (NaOH) solution that is neutralized by 200 mL of 2 mol/L aqueous hydrochloric acid solution?

A
400 mL
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B
200 mL
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C
250 mL
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D
350 mL
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Solution

The correct option is A 400 mL
We know that, in the case of neutralisation,
Meq.of Acid = Meq. of Base
i.e. Meq.of HCl = Meq. of NaOH
NHCl×VmL=NNaOH×VmL

Also, N = M × nfactor
nfactor of HCl=1
nfactor of NaOH=1
Thus, NHCl=MHCl and NNaOH=MNaOH
Hence,
2×200=1× V
(Where V is the volume of NaOH in mL)
Volume of NaOH = 400 mL

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