Calculate the volume of a frustum cone given above:

450

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411

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487

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467

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Solution

The correct option is D $487$
Volume of the frustum cone = $\frac{1}{3} π h (R^{2} + r^{2} + R r)$
= $\frac{1}{3} π \times 15 (5^{2} + 1^{2} + 5)$
= $\frac{1}{3} π \times 465$
= $\frac{1}{3} \times 3.14 \times 465$
= $\approx 487$

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Calculate the volume of a frustum cone :

Given D = 2 cm, d = 1 cm, h = 15 cm.

π

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= \frac{1}{3} π h ({r_{1}}^{2} + r_{1} r_{2} + {r_{2}}^{2})

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