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Stoichiometric Calculations

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Question

Calculate the volume of 'carbon dioxide at NTP evolved by strong heating of 20 g calcium carbonate.

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Solution

The balanced equation is:

$C a C O_{3} 1 m o l 100 g \to C a O + C O_{2} 1 m o l = 22.4 l i t r e a t N T P$
$100 g$ of $C a C O_{3}$ evolve carbon dioxide = 22.4 litre
$20 g$ $C a C O_{3}$ will evolve carbon dioxide
$= \frac{22.4}{100} \times = 4.48 l i t r e$

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