Calculate the volume of dry air at S-T-P- that occupies 28 cm3 at 14-C and 750 mm Hg pressure when saturated with water vapour- The vapour pressure of water at 14-C is 12 mm Hg-

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The Ideal Gas Equation

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Question

Calculate the volume of dry air at S.T.P. that occupies $28 c m^{3}$ at $14^{\circ} C$ and 750 mm Hg pressure when saturated with water vapour. The vapour pressure of water at $14^{\circ} C$ is 12 mm Hg.

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Solution

The pressure of dry air = 750 – 12 = 738 mmHg

Now,

$P subscript 1 equals 738 m m space H g V subscript 1 equals 28 m l T subscript 1 equals 14 degree c equals open parentheses 273 plus 14 close parentheses K equals 287 K P subscript 2 equals 760 m m H g space open parentheses p r e s s u r e space a t space S T P close parentheses V subscript 2 equals ? T subscript 2 equals 0 degree C equals 273 K space space open parentheses T e m p e r a t u r e space a t space S T P close parentheses u sin g space g a s space e q u a t i o n fraction numerator P subscript 1 V subscript 1 over denominator T subscript 1 end fraction equals fraction numerator P subscript 2 V subscript 2 over denominator T subscript 2 end fraction fraction numerator 738 cross times 28 over denominator 287 end fraction equals fraction numerator 760 cross times V subscript 2 over denominator 273 end fraction V subscript 2 equals 25.86 m l$

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Calculate the volume of dry air at S.T.P. that occupies 28cm3 at 14∘C and 750 mm Hg pressure when saturated with water vapour. The vapour pressure of water at 14∘C is 12 mm Hg.

The pressure of dry air = 750 – 12 = 738 mmHg Now,

Calculate the volume of dry air at S.T.P. that occupies $28 c m^{3}$ at $14^{\circ} C$ and 750 mm Hg pressure when saturated with water vapour. The vapour pressure of water at $14^{\circ} C$ is 12 mm Hg.