Calculate the volume of hydrogen gas evolved when 2g of ammonia gas is heated at STP.

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Solution

$T h e s t o i c h i o m e t r i c e q u a t i o n i s 2 N H_{3} \to N_{2} + 3 H_{2} 2 \times 17 g = 34 g N H_{3} p r o d u c e s 3 m o l e s o f h y d r o g e n = 3 \times 22.4 = 67.2 L o f h y d r o g e n 2 g o f a m m o n i a p r o d u c e s = \frac{67.2}{34} \times 2 = 3.95 L o f h y d r o g e n g a s .$

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Calculate the volume of hydrogen gas evolved when 2g of ammonia gas is heated at STP.

The stoichiometric equation is2 NH3 → N2 + 3 H22 × 17 g = 34 g NH3 produces 3 moles of hydrogen = 3 × 22.4 =67.2 L of hydrogen 2 g of ammonia produces = 67.234 × 2 = 3.95 L of hydrogen gas.