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Question

Calculate the volume of NH3 at
STP produced if 2.00*1000g
dinitrogen reacts with 1.00*1000g
​of dihydrogen.

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Solution

The stochiometric reaction isN2 + 3 H2 2 NH328 g 6 g 2 × 17 = 34 gGiven weight2000 g 1000 gAs per the stochiometric,28 g of nitrogen reacts with 6 g of hydrogen2000 g nitrogen reacts with = 628 × 2000 = 428.57 g of hydrogenBut the given amount of hydrogen = 1000 g So nitrogen acts as a limiting reagent.28 g of nitrogen gives 34 g of 2000 g of nitrogen gives = 3428 × 2000 = 2428.57 g of ammonia = 142.86 mole of ammonia1 mole of any gas occupies 22.4 L at STP142.86 mole occupies = 22.41 × 142.86 = 3200 L

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