Calculate the volume of SO2 liberated at STP when 15g of Cu reacts with excess concentrated H2SO4
Cu+ 2H2SO4 ------------------- CuSO4 + 2H2O + SO2

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Solution

Cu+ 2H₂SO₄ ------------------- CuSO₄+ 2H₂O + SO₂

From the given equation,
63.5 g ---------------- 1 volume of SO₂ (22.4 L at STP)

15 g -------------- ?

$\frac{22.4}{63.5} \times 15$ = 5.29 L

5.29 L of SO₂ is produced by 15 g Cu

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