The correct option is C 27419.25 cm−1
The shortest wavelength transition in the Balmer series corresponds to the transition: n=2→n=∞
The shortest wavelength requires the highest energy for an electron to jump from n = 2 to n=∞
So, n1=2 and n2=∞
Using the formula:
¯v=RH(1n21−1n22) where RH = Rydberg constant
¯v=(109677 cm−1)(122−1∞2)On solving,¯v=27419.25 cm−1