Calculate the wavelength of a photon having an energy of 3 eV. Take $h = 6.6 \times 10^{- 34} J s$

4.125 \times 10^{3} \circ A

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4.125 \times 10^{4} \circ A

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5.125 \times 10^{3} \circ A

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7.125 \times 10^{3} \circ A

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Solution

The correct option is A $4.125 \times 10^{3} \circ A$
$1 e V = 1.6 \times 10^{- 19} J$
From Planck's quantum theory, E = $\frac{h c}{λ}$
where E = energy of the photon
$λ$ = Wavelength of the photon
So, $λ = \frac{h c}{E} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{3 \times 1.6 \times 10^{- 19}}$
$λ = 4.125 \times 10^{3} \circ A$

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