Calculate the wavelength of the spectral line, when the electron in the hydrogen atom undergoes a transition from the energy level 4 to energy level 2.

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Solution

$¯ ¯¯ ¯ V = R [\frac{1}{x_{1}^{2}} - \frac{1}{x_{2}^{2}}]$
$= 109677 [\frac{1}{4^{2}} - \frac{1}{2^{2}}] c m^{- 1}$
[Here $R = 108677 c m^{- 1}, x_{1} = 4; x_{2} = 2$
$= 20564.4 c m^{- 1}]$
$λ = \frac{1}{V} = \frac{1}{20564.4}$
$= 486 \times 10^{- 7} c m$
$= 486 \times 10^{- 9} c m$
$= 486 n m$ .

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Similar questions

Q. Calculate the wavelength of the spectral line, when an electron in the hydrogen atom undergoes a transition from the energy level 4 to energy level 2.

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Calculate the wavelength of the spectral line, when the electron in the hydrogen atom undergoes a transition from the energy level 4 to energy level 2.

¯¯¯¯V=R[1x21−1x22]=109677[142−122]cm−1[Here R=108677 cm−1,x1=4;x2=2=20564.4 cm−1]λ=1V=120564.4=486×10−7cm=486×10−9cm=486 nm.