Calculate the weight of 0.1 mole of sodium carbonate.

1.06 g

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11.06 g

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10.6 g

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1.106 g

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Solution

The correct option is D 10.6 g
$M o l e = \frac{w e i g h t (w)}{M o l e c u l a r w e i g h t (M . W)}$

$w = M o l e \times M . W$

$= 0.1 \times 106$ ( $∵ M . W$ of $N a_{2} C O_{3} = 106$ )

$w = 10.6 g m$

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Calculate the weight of 0.1 moles of Na₂CO₃?

0.7

H C l

N a_{2} C O_{3} + 2 H C l \to 2 N a C l + C O_{2} + H_{2} O

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