Calculate the weight of $0.885$ moles of $M g {(N O_{3})}_{2}$ .

13.1 g

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131 g

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130 g

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88.5 g

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Solution

The correct option is B $131 g$
given that
$0.885$ moles of $M g (N O_{3})_{2}$
moles $= \frac{w e i g h t o f m g (N O_{3})_{2}}{m o l e c u l a r w e i g h t}$
$0.885 = \frac{w e i g h t o f m g (N O_{3})_{2}}{148}$
Weight of mg $(N O_{3})_{2} = 131 g$

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