Calculate:
The weight of $10^{22}$ atoms of carbon.
[ $C = 12$ , Avogadro’s No. $= 6 \times 10^{23}$ ]

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Solution

$6.022 \times 10^{23}$ atoms of carbon weigh $\to 12 g$
1 atom of carbon weighs $\to \frac{12}{6 \times 10^{23}}$
$10^{22}$ atoms of carbon will weigh $\to \frac{12}{6 \times 10^{23}} \times 10^{22} = \frac{12}{60} = \frac{1}{5} = 0.2 g$

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Similar questions

Calculate the mass of
(i) 10²² atoms of sulphur,
(ii) 0.1 mole of carbon dioxide.

[Atomic mass: S = 32, C = 12 and O = 16 and Avogadro's Number = 6 × 10²³]

(a)

(i) Calculate the volume of 320 of $S O_{2}$ at STP. (Atomic mass : S = 32 and O = 16).
(ii) State Gay-Lussac's law of combining volume
(iii) Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane $(C_{3} H_{8})$ (Atomic mass; C = 12, 0 = 16, H = 1, Molar volume $- 22.4 d m^{3}$

(b)

(i) An organic compound with vapour density = 94 contains
C = 12.67% H = 2.13 % and Br = 85.11% Find the molecular formula.
[Atomic mass ; C = 12, H = 1, Br = 80]
(ii) Calculate the mass of
(1) $10^{22}$ Atoms of sulphur.
(2) 0.1 mole of carbon dioxide.
[Atomic mass; S = 32, C = 12 and O = 16 and Avogadro's number $= 6 \times 10^{23}$