Calculate the weight of $3.0$ moles of $K C l O_{3}$ .

245 g

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249 g

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367.5 g

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24.5 g

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Solution

The correct option is C $367.5 g$
given that
$3$ mole of $K C l O_{3}$
$\frac{w e i g h t o f K C l O_{3}}{m o l e c u l a r w e i g h t} = 3$ mole
Weight of $K C l O_{3} = 3 \times 122.5$
$= 367.5 g$

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Calculate the weight of 3.0 moles of KClO3.

The correct option is C 367.5ggiven that 3 mole of KClO3weightofKClO3molecularweight=3 mole Weight of KClO3=3×122.5=367.5g

Calculate the weight of $3.0$ moles of $K C l O_{3}$ .

The correct option is C $367.5 g$
given that
$3$ mole of $K C l O_{3}$
$\frac{w e i g h t o f K C l O_{3}}{m o l e c u l a r w e i g h t} = 3$ mole
Weight of $K C l O_{3} = 3 \times 122.5$
$= 367.5 g$