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Mole Concept and Avogadro's Number

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Question

Calculate the weight of CO having same number of oxygen atoms as are present in 88 grams of CO2.

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Solution

No of oxygen atoms in CO2 = 2× 88/44 × Avogadro's constant

no of oxygen atoms = weight of CO/28 × Avogadro's constant

no of oxygen atoms in CO2 = no of oxygen atoms in CO

2× 88/44 = weight of CO/28

weight of CO = 112 g

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