MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Electric Power

Calculate the...

Question

Calculate the weight of gold having specific heat capacity 0.13 J (C) g which is heated from 25 to 300 degree centigrade, where the heat absorbed is 1500J.

Open in App

Solution

Given :
q = 1500 J
m = ?
Cp = 0.13J/gC
dT = 300-25 = 275 C
q = m x Cp x dT
rearrange the equation
m = q/Cp x dT
m = 1500 J / (0.13 J/gC x 275 C)
m =41.958 g
m = 41.96g ( is the weight of gold)

Suggest Corrections

thumbs-up

1

Similar questions

Q. Calculate the weight of gold having specific heat capacity 0.13 J (C) g which is heated from 25 to 300 degree centigrade, where the heat absorbed is 1500J.

Q. Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410

J K g^{- 1} K^{- 1}

. How much heat energy will be required to increase the temperature of the vessel from

25^{0} C

35^{0} C

?

Which of the following energy is absorbed during the change of state of a substance?

(a) specific heat (b) latent heat (c) heat capacity (d) heat of solution

Q. The heat produced on complete combustion of

20 g

of a fuel could raise the temperature of

1.5 k g

of water from 25

^{\circ} C

^{\circ} C

. Calculate the calorific value of the fuel, if the specific heat capacity of water is

4.2 J g^{- 1}

^{o}

C^{- 1}

. Assume that the heat absorbed by the container is negligible.

1500

J of heat energy is required to raise the temperature of a metallic ball of

300

5^{\circ} C

15^{\circ} C

. Calculate the specific heat capacity of the metal ball.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Powerful Current

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard X Physics

Join BYJU'S Learning Program

CrossIcon