Calculate the weight of one molecule of oxygen.
(Avogadro's number = 6 × 10²³, [O] = 16)

Open in App

Solution

Atomic mass of oxygen = 16 g mol⁻¹
Molecular mass of oxygen = (2 $\times$ 16) g mol⁻¹ = 32 g mol⁻¹
Mass of 6 × 10²³ molecules of oxygen = 32 g
Mass of one molecule of oxygen = $\frac{32 g {mol}^{- 1}}{6 \times 10^{23} {mol}^{- 1}} = 5.3 \times 10^{- 23} g$

Suggest Corrections

Similar questions

Calculate the number of molecules in 12.8 g of sulphur dioxide gas. Take Avogadro's number as 6 × 10²³.
[S = 32, O = 16]

12 \times 10^{24}

6 \times 10^{23}

[O = 16]

O = O

498 kJ/mol

6 \times 10^{23}

6.6 \times 10^{- 34} J s

Calculate the mass of
(i) 10²² atoms of sulphur,
(ii) 0.1 mole of carbon dioxide.

[Atomic mass: S = 32, C = 12 and O = 16 and Avogadro's Number = 6 × 10²³]

Calculate the mass of 10²² atoms of sulphur.

[Atomic mass: S = 32, C = 12 and O=16 and Avogadro's Number = 6 x 10²³]

Join BYJU'S Learning Program