Calculate the work done by 10g of an ideal gas of molecular weight 44g in expanding reversibly and isothermaly from a volume of 5Lto10Lat300K.
A
w=−103cal
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B
w=−94cal
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C
w=−9.4cal
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D
None of these
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Solution
The correct option is Bw=−94cal Work done in an isothermal reversible process is given as: w=−2.303nRTlog10V2V1 Number of moles of ideal gas n = 10g44gmol−1 = 1044mol
R=2calK−1mol−1 T=300K V2V1= 105 = 2
On substituting the values we get, w=−2.303×1044×2×300×log2 On solving, w=−93.93cal